In the case of thorium `(A = 232 and Z = 90)`, we obtain an isotope of lead `(A = 208 and Z = 82)` after some radiactive disintegrations. The number of `alpha` and `beta` particle emitted are respectively.

Answer

`6alpha and 4 beta`

Explanation

Let x be the number of alpha particles `(._(2)He^(4))` any y be the no. of `beta` particles `(._(-1)e^(0))`
`:.` Change in mass number, `4x=232=208=24`
`x=24/4=6`
chang in charge number, `2x-y=90-82=8`
`y=2x-8=12-8=4`