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An isotope .(92)U^(238) decays successiv...

An isotope `._(92)U^(238)` decays successively to form `._(90)Th^(234),._(91)Pa^(234),._(90)Th^(234),._(90)Th^(230)` and `._(88)Ra^(226)`. What are the radiations emitted in these five steps?

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The correct Answer is:
`alpha,beta, beta, alpha,alpha`
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