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What is the power output of a .(92) U^(2...

What is the power output of a `._(92) U^(235)` reactor if it is takes `30` days to use up `2 kg` of fuel, and if each fission gives `185 MeV` of usable energy ?.

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Verified by Experts

The correct Answer is:
`58.3xx10^(6)watt`

P=?
Mass of fuel consumed/sec `=(2xx10^(3))/(30xx24xx60xx60)g`
Number of atoms undergoing fission
`=(6xx10^(23)xx2xx10^(3))/(235xx30xx24xx60xx60)=1.97xx10^(18)`
Power =Energy released/sec
`=1.97xx10^(18)xx185xMeV//sec`
`=364.45xx10^(18)xx1.6xx10^(-13)watt`
`P=58.3xx10^(6)"watt"`
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