The gravitational force between a H-atom and another particle of mass m will be given by Newton's law: `F=G (M.m)/(r^(2)`, where r is in km and

Options

A. `M=m_("proton")+m_("electron")`
B. `M=M_("proton")+m_("electron")-B/(c^(2)) (B=13.6eV)`
C. `M` is not related to the mass of the hydrogen atom
D. `M=m_("proton")+m_("electron")-(|V|)/(c^(2)) (|V|)`=magnitude of the potential energy of electron in the H-atom)

Answer

B

Explanation

In the relation `F=(GMm)/(r^(2))`,
M=effective mass of hydrogen atom
=mass of proton+mass of electron `-B//c^(2)`, where B is B.E. of hydrogen atom=13.6eV. Choice (b) is correct.