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The de - Broglie wavelength of a neutron...

The de - Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature `T ("kelvin")` and mass `m`, is

A

`lambda=h/(sqrt(3mKT))`

B

`lambda=h/(sqrt(6mKT))`

C

`lambda=h/(sqrt(5mKT))`

D

`lambda=h/(sqrt(2mKT))`

Text Solution

Verified by Experts

The correct Answer is:
A
As `1/2mv^(2)=3/2kT :. mv^(2)=3kT`
or `m^(2)v^(2)=3mkT`
or `mv=sqrt(3mkT)`
`lambda=h/(mv)=h/(sqrt(3mkT))`
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