A nucleus `._Z^A X` has mass represented by `M(A, Z)`. If `M_p` and `M_p` denote the mass of proton and neutron respectively and `BE` the binding energy (in MeV), then :

Options

A. `B.E=[ZM_(p)-(A-Z)M_(n)-M(A,Z)]c^(2)`
B. `B.E=[ZM_(p)-AM_(n)-M(A,Z)]c^(2)`
C. `B.E=M(A,Z)-ZM_(p)-(A-Z)Mn`
D. `B.E=[M(A,Z)-ZM_(p)-(A-Z)Mn]c^(2)`

Answer

A

Explanation

In the nucleus `._(Z)Z^(A)`, number of proton=Z
number of neutrons =(A-Z)
As `B.E.= (Deltam)c^(2)`
`B.E.=[ZM_(p)+(A-Z)M_(n)-M(A,Z)]c^(2)MeV`