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If the binding energy per nucleon in (3...

If the binding energy per nucleon in `_(3)^(7) Li` and `_(2)^(4)He` nuclei are 5.60 MeV and 7.06MeV respectively then in the reaction
`P +_(3)^(7) Li rarr 2 _(2)^(4) He`
energy of proton must be

A

`19.6MeV`

B

`-2.4MeV`

C

`8.4MeV`

D

`17.3MeV`

Text Solution

Verified by Experts

The correct Answer is:
D
In the given nuclear reaction,
`Q=2xxB.E of He-"B.E of Lithium"`
`=2(4xx7.06)-(7xx5.60)`
`=56.48-39.2=17.3 MeV`
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