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The binding energies per nucleon for a d...

The binding energies per nucleon for a deuteron and an `alpha-`particle are `x_1` and `x_2` respectively. What will be the energy `Q` released in the following reaction ?
`._1H^2 + ._1H^2 rarr ._2He^4 + Q`.

A

`4(x_(1)+x_(2))`

B

`4(x_(1)-x_(2))`

C

`2(x_(2)-x_(1))`

D

`2(x_(1)+x_(2))`

Text Solution

Verified by Experts

The correct Answer is:
B
The energy released =B.E. of product nuclei-B.E. of reacting nuclei
`=4x_(2)-2(2x_(1))=4x_(2)-4x_(1)=4(x_(2)-x_(1))`
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