Let `A_(0)` be the area enclined by the orbit in a hydrogen atom .The graph of in `(A_(0) //A_(1))` against `ln(n)`

Options

A. will be a circle
B. will be a monotonically increasing non-linear curve
C. will be a straight line with slope 4
D. will pass through the origin

Answer

C, D

Explanation

As `r prop n^(2) :. (A_(n))/(A_(1))=(n^(4))/1`
`ln ((A_(n))/(A_(1)))=4ln (n)`.
The graph of `ln ((A_(n))/(A_(1)))` against In (n) will be a straight line with slope =4. Also, it will pass through the origin.