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A deutron is bombarded on .8 O^16 nucleu...

A deutron is bombarded on `._8 O^16` nucleus and `alpha-`particle is emitted. The product nucleus is.

A

`._(7)N^(14)`

B

`._(7)N^(13)`

C

`._(4)Be^(9)`

D

`._(5)B^(10)`

Text Solution

Verified by Experts

The correct Answer is:
A
`._(8)O^(16)+._(1)D^(2) to ._(2)X^(A)+._(2)He^(4)`
As `A+4=16+2 :. A=18-4=14`
As `Z+2=8+1 :. Z=9-2=7`
`:. ._(Z)X^(A)= ._(7)N^(14)`
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