Two deutrons each of mass m fuse to form...

Two deutrons each of mass m fuse to form helium resulting in release of energy E. The mass of helium formed is

`m+E//c^(2)`

`2m+E//c^(2)`

`E//mc^(2)`

`2m-E//c^(2)`

Text Solution

Verified by Experts

The correct Answer is:

Total mass before fusion =2m
Mass converted into energy in this process `=E//c^(2)`
`:.` Mass of He formed =`(2m=E//c^(2))`

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