In a p-n junction diode the reverse saturation current is `10^(-5)A` at `27^(@)C`. Find the forward current for a voltage of `0.2 V`. Given exp. `(7.62)=2038.6,k=1.4xx10^(-23)JK^(-1)`.
Text Solution
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The current in the junction diode is given by `I=I_(0)[e^(eV//kT)-1]` where, `I_(0)=` reverse saturation current`=10^(-5)A, T=27+273=300K`. `I=10^(-5)[e^((1.6xx10^(-19)xx0.2)/(1.4xx10^(-23)xx300))-1]=10^(-5)[e^(7.62)-1]=10^(-5)[2038.6-1]` `=2037.6xx10^(-5)=2.0376xx10(-2)=2.04xx10^(-2)A`
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