Let us find the difference of `(111101)_(2)` and `(110010)_(2)`

Explanation

`{:("1 1 1 1 0 1"),("1 1 0 0 1 0"),(ulbar("0 0 1 0 1 1")):}`
In the first column (from extreme right), the subtraction of binary 0 from binary 1 gives 1. In the second column, the subtraction of binary 1 from binary 0 is not possible, so we have a carry of 1 from third column for second column, leaving binary 0 at third column and making 10 at second column. Then subtraction of binary 1 from 10 gives 1 at second column. In the third column, the subtraction of binary 0 from binary 0 (left after carry of 1) is 0. In the fourth coiumn, the subtraction of binary 0 from binary 1 gives 1. In the fifth and sixth column, the subtraction of binary 1 from binary 1 gives 0 at each place. Thus
`(111101)_(2)-(110010)_(2)=(001011)_(2)`