The mean free path of conduction electrons in copper is about `4 xx 10^(-8)m`. Find the electric field which can give, on an avrage, `2 eV` energy to a conduction electron in a block of copper.
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Here, mean free path, `d=4xx10^(-8)m,` Electric field, `E=?`, Energy of electron `=2eV` Force on electron in electric field `=eE` The work done on electron when it moves through distance `d=eEd.` This work done is equal to the energy transferred to the electron, so `e Ed=2eV` or `E=(2V)/d=(2V)/(4xx10^(-8)m)=5xx10^(7) V//m`
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