Suppose the energy liberated in the recombination of a hole-electron pair is converted into electromagnatic radiation. If the maximum wavelength emitted is 660nm, what is the band width? (Use `h=6.6xx10^(-34) J-s)`
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Here, `lambda=660nm=660xx10^(-9)m` Bandwidth is equal to the energy corresponding to wavelength lambda, which is given by `E_(g)=(hc)/lambda=((6.6xx10^(-34))xx(3xx10^(8)))/(660xx10^(-9))=J` `=((6.6xx10^(-34))xx(3xx10^(8)))/((660xx10^(-9))xx(1.6xx10^(-19)))eV=1.875eV`
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