Find the maximum wavelength of electromagnatic radiation which can creat a hole-electron pair in silicon. The band is silicon is `1.1 eV`. [Use `h = 6.6xx10^(-34) Js , c=3xx10^(8)ms^(-1), e=1.6xx10^(-19)C.`
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Here, `E_(g)=0.72 eV` `=0.72xx(1.6xx10^(-19))J`. If `lambda` is the maximum wavelength of electromagnetic radation, which can creat a hole-electron pair in germanium, then `E^(g)=(hc)/lambda` or `lambda=(hc)/E^(g)=((6.62xx10^(-34))xx(3xx10^(8)))/(0.72xx1.6xx10^(-19))` `=1.724xx10^(-6)m`
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