Calculate the value of output voltage `V_(0)` (in V) if the Si diode and Ge diode conduct at `0.7V` and `0.3 V` respectively. Fig.
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The correct Answer is:
11.7
(i) As germanium diode conducts at lower voltage (0.3V) than silicon diode which conduct at 0.7 V, so the current will prefer to pass through germanium diode. Then output voltage, `V_(0)=12-0.3=11.7V` and current, `I=V_(0)/R=11.7/(5xx10^(3))=2.34xx10^(-3)A=2.34mA` (ii) When germanium diode is reverse biased, it will offer very large resistance to the current flowing through it. Now the current will flow through the silicon diode. Then output voltage, `V_(0)=12-0.7=11.3V` and current, `I=V_(0)/R=11.3/(5xx10^(3))=2.26xx10^(-3)A` `=2.26mA`
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