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An n - p- n transistor is connected in ...

An n - p- n transistor is connected in common - emitter configuraration in which collector supply is 8 V and the voltage drop across the load resistance of ` 800 Omega ` connected in the collector circuit is 0.8 V . If current amplification factor is 25 , determine collector - emitter voltage and base current . If the internal resistance of the transistor is ` 200 Omega ` , calculate the voltage gain and the power gain.

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An p-n-n transistor amplifier circuit with common-emiter mode is shown in fig.

Here, `V_(C C)=8V, R_(L)=800Omega`,
Voltage drop across `R_(L)=0.8V`
Collector current, `I_C=("voltage drop across" R_(L))/R_(L)`
`=0.8/800=10^(-3)A`
Collector-emitter voltage, `V_(CE)=V_(C C)-I_CR_(L)`
`=8-0.8=7.2V`
Base current, `I_B=I_C/beta=10^(-3)/25=40xx10^(-6)A`
`=40 muA`
Voltage gain, `A_(V)=betaR_(L)/R_B=25xx800/200=100`
Power gain,
`A_(P)=beta^(2)R_(L)/R_B=(25)^(2)xx800/200=2500`
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