In an n-p-n transistor `10^(10)` electrons enter the emitter in `10^(-6)`s. If 2% of the electrons are lost in the base, find the current transfer ratio and the current amplification factor.

Explanation

To solve the problem step by step, we will follow the given information and apply the relevant formulas.

### Step 1: Determine the number of electrons entering the emitter
Given that `10^10` electrons enter the emitter in `10^(-6)` seconds.

### Step 2: Calculate the number of electrons lost in the base
Since 2% of the electrons are lost in the base, we can calculate the number of electrons that reach the collector:
- Electrons lost = 2% of `10^10` = `0.02 * 10^10` = `2 * 10^8`
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