Let A, B and C be any three logic variables, prove the following Boolean identity. `A.B.C+A.barB.C+A.B.barC=A.(B+C)`
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Taking L.H.S. of the given identy, we have `=A.B.C+barB.C+B.barC` `=A.(B.C+barB.C+barB.C]` `=A.[B.(C+barC) +barB.C]` `=A.[B.(1)+barB.C]=A.[B+barB.C]` `( :' C+barC=1)` `=A.(B+C) ( :' B+barB.C=B+C)` Which is the right hand side of the gives identity.
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