In V-I characteristics of a p-n junction diode, why is the current under reverse bias almost independence of the applied potential upto a critical voltage?
Text Solution
Verified by Experts
When a p-n junction is reverse biased, a very small current (of the order of few `muA`) flows due to drifting of minority charge carriers whose number density remain constant upto the critical voltage. As result of it, the current under a reverse bias is almost independent of the applied potential upto critical voltage.
Topper's Solved these Questions
ELECTRONIC DEVICES
PRADEEP|Exercise SAMPLE PROBLEM|2 Videos
ELECTRONIC DEVICES
PRADEEP|Exercise CONCEPTUAL PROBLEMS|1 Videos
ELECTROMAGNETIC WAVES
PRADEEP|Exercise II Focus multiple choice question|5 Videos
ELECTROSTATICS
PRADEEP|Exercise ASSERTION-REASON TYPE QUESTIONS|2 Videos
Similar Questions
Explore conceptually related problems
In V - I characteristics of p-n junction in reverse biasing results in
When a p-n junction diode is reverse biased
A p-n junction diode is reverse biased. Then
Draw V-I characterictics of a p-n junction diode. Why does the reverse current show a sudden increase at the critical voltage? Name any semiconductor device which operates under the reverse bias in the breakdown region.
No bias is applied to a P-N junction, then the current-