Give the ratio of number of holes and the number of conduction electrons in a (i) pure semiconnductor (ii) n-type semiconductor and (iii) p-type semiconductor.

Explanation

To solve the question regarding the ratio of the number of holes (NH) to the number of conduction electrons (NE) in different types of semiconductors, we will analyze each type step by step.

### Step 1: Pure Semiconductor
In a pure semiconductor, the number of conduction electrons is equal to the number of holes. This is because pure semiconductors have an equal number of electrons that can move freely and holes that represent the absence of electrons.

- **Mathematical Representation**:
\[
NE = NH
...