Derive a relation between current gain of common emitter amplifier.
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For a junction transistor, we know `I_(e)=I_b+I_c` ...(i) Current gain for common base amplifier, `alpha=I_c//I_(e)` Current gain for common emitter amplifier, `beta=I_c//I_b` From(i), `I_(e)/I_c=I_b/I_c+1` or `1/alpha=1/beta+1` or `1/beta=1/alpha-1=(1-alpha)/alpha` or `beta=alpha/(1-alpha)`
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