The ratio of number density of free electrons to holes for two different materials, A and B, are (i) equal to one and (ii) less than one respectively. Name the type of semiconductor to which A and B belong. Draw energy level diagram for A and B.
Text Solution
AI Generated Solution
To solve the problem, we need to analyze the given information about the number density of free electrons and holes in two different materials, A and B. We will determine the type of semiconductor each material represents and then draw their energy level diagrams.
### Step-by-Step Solution:
1. **Understanding the Ratio of Number Densities**:
- We are given the ratio of the number density of free electrons (N_E) to holes (N_H) for two materials:
- For material A, N_E/N_H = 1
- For material B, N_E/N_H < 1
...
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