A p-n junction is fabricated from a semiconductor with band gap of `2.8eV`. Can it detect a wavelength of `6000nm`?
Text Solution
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Energy of wavelength to be detected `E=(hc)/lambda=((6.6xx10^(-34))xx(3xx10^(8)))/(600xx10^(-9)xx1.6xx10^(-19))eV=0.2eV` As `E lt E_(g)`, so p-n junction cannot detect the radiation of given wavelength.
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