In a full wave junction diode rectifier, the input a.c. has r.m.s. value of `20 V`. The transformer used is a step up transformer having primary and secondary turns ratio `1: 2`. Calculate the d.c. and a.c. voltade in the recitified output.
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Here, `V_(rms)=20V`, Peak voltage of input voltage, `V_(0)=sqrt(2)V_(rms)=sqrt(2)xx20=28.28V` Since the transformer is a step up transformer, having transformation ratio 1:2, the maximum value of the output voltage of the transformer applied to the diode will be `V_(0)^(')=2xxV_(0)=2xx28.28V` D.C. voltage `=(2V_(0)^('))/pi=(2xx(2xx28.28))/((22//7))=36V` Output a.c. voltage `=0.48V_(0)^(')` `=0.48xx(2xx28.28)=27.14V`
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