A transistor is used in common-emitter mode in an amplifier circuit. When a signal of 30mV is added to the base-emitter voltage, the base current changes by `30muA` and collector current by 3mA. The load resistance is`5kOmega`. Calculate (i) the current gain `beta_(ac)` (ii) the input resistance `R_(BE)` (iii) transconductance and (iv) voltage gain.
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(i) `beta_(ac)=(DeltaI_c)/(DeltaI_b)=(3mA)/(30muA)=(3xx10^(-3)A)/(30xx10^(-6)A)=100` (ii) The input resistance `R_(BE)=(DeltaV_(BE))/(DeltaI_b)=(30mV)/(30muA)=1000Omega` (iii) Transconductance, `g_(m)=(DeltaI_b)/(DeltaV_(BE))=(3mA)/(30mV)` `=0.1Omega^(-1) or S` (iv)The output voltage, corresponding to signal voltage `V_(0)=R_(L)DeltaI_c=(5kOmega)xx(3mA)=15V` Voltage gain` = ("output voltage")/("input voltage") =(15V)/(30mV)=500`
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