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A n-p-n transistor is connected in commo...

A n-p-n transistor is connected in common emitter configuration in which collector supply is 9V and the voltage drop across the load resistance of `700Omega` connected to the collector circuit is 0.7V. If the current amplification factor alpha is `25//26`, determine collector emitter voltage and base current. If the input resistance of the transistor is `100Omega`, calculate the voltage gain and the power gain.

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An n-p-n transistor amplifier circuit with common emitter mode is shown in Fig.9(APC).4.

Here, `V_(C C)=9V, R_(L)=700Omega`,
Voltage drop across `R_(L)=V_(0)=0.7V`
Collector-emitter voltage,
`V_(CE)=V_(C C)-V_(O)=9-0.7=8.3V`
Collector current, `I_C =("voltage drop across" R_(L))/R_(L)`
`=0.7/700=10^(-3)A`
Current gain, `alpha=I_C/I_(E)`
or `I_(E)=I_C/alpha=(10^(-3)A)/(25//26)=26/25xx10^(-3)A`
Base current, `I_C=I_(E)-I_B`
`=26/25xx10^(-3)-10^(-3)=1/25xx10^(-3)A=0.04mA`
`beta=I_C/I_B=(10^(-3)A)/((1//25)xx10^(-3)A)=25`
Here, the resistance of input circuit `R_(i)=100Omega` input voltage,`V_(i)=R_(i)xxI_B=100xx(0.04xx10^(-3))`
`=4xx10^(-3)V`
Voltage gain, `A_(V)=V_(0)/V_(i)=0.7/(4xx10^(-3))=175`
Power gain `A_(P)= `current gain xx voltage gain
`betaxxA_(v)=25xx175=4375`
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