For current in emitter-base circuit `V_(BE)=E_(CE)-I_(B)R_(B)=0`
or `I_(B)=E_(CE)/R_B=(5V)/(200kOmega)=25muA`
For current in collector emitter circuit
`V_(CE)=E_(CE)-I_(C) R_(L)=0`
or `I_(C)=E_(CE)/R_(L)=(5V)/(1.5kOmega)=3.33mA`
Now `beta=I_C/I_B=(3.33mA)/(25muA)=(3.33xx10^(-3)A)/(25xx10^(-6)A)`
`=133.2`
The output waveform will be antophase as it is common-emitter amplifier.