If the resistance `R_1` is increased , how will the readings of the ammeter and voltmeter change? `
Text Solution
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`I_b=(V_(BB)-V_(BE))/R_(1)` If `R_(1)` is increased `I_b` will decrease. Since `beta=I_c//I_b` or `I_=betaI_b`, therefore as `I_b` decreases. Due to it, ammeter reading will decrease. The potential difference across `R_(2)` also decreases, i.e., voltmeter reading also decreases.
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