In which region transistor with `h_(fe)=80` operates as shown in Fig. Also find `R_(B)`.
Text Solution
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Since `V_(CB) lt V_(c c )` and not equal to zero, therefore, Transistor operates in avtive region: Current in the collector circuit is `I_(c)=((9-5)V)/(2kOmega)=2mA` `h_(fe)=I_c/I_b` or `I_b=I_c/H_(fe)=(2mA)/80=2.5xx10^(-5)A` we know that `V_(BE)` in active region is `0.7V`, therfore, `R_(B)=((3.2-0.7)V)/((2.5xx10^(-5))A)=92xx10^(3)Omega=92kOmega`
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