The applied input a.c. to a half wave rectifier is 120 watt. The d.c. output is 50 watt. What is the rectification effeciency and power effeciency?

Explanation

Rectification effeciency
`=(d.c. "output power")/(a.c. "input power")xx100`
`=50/120xx100=41.67%`
Power effeciency
`=(d.c. "output power")/(a.c. "input power for half cycle")xx100`
`50/((120//2))xx100=83.33%`