A transistor, connected in common emitter configuration, has input resistance `R_(i)=2kOmega` and load resistance `6kOmega`. If `beta=60` and an input signal `10mV` is applied, calculate the (i) resistance gain, (ii) voltage gain (iii) the power gain and (iv) the value of the output signal.

Explanation

(i) Resistance gain `=R_(0)/R_(i)=6/2=3`
(ii) Voltage gain, `A_(V)=betaR_(0)/R_(i)=60xx3=180`
(iii) Power gain `=beta^(2)xxR_(0)/R_(i)=(60)^(2)xx3=10800`