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In Fig.assuming the diode to be ideal...

In Fig.assuming the diode to be ideal

A

`D_(1)` is forward biased and `D_(2)` is reverse biased and hence current flows from A to B

B

`D_(2)` is forward biased and `D_(1)` is reverse biased and hence no current flows from B to A and vice versa

C

`D_(1)` and `D_(2)` are both forward biased and hence current flows from A to B

D

`D_(1)` and `D_(2)` are both reverse biased and hence no current flows from A to B and vice versa

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The correct Answer is:
B

In the given circuit , p-side of p-n junction `D_(1)` is connected to lower voltage and n-side of `D_(1)` to higher voltage. Therefore, `D_(1)` is reverse biased. The p-side of p-n junction `D_(2)` is at higher potential and n-side of `D_(2)` is at lower potential. Therefore, `D_(2)` is forward biased. Hence, current flows through the junction from B to A, i.e.,
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