Truth table for the given circuit (Fig.)is

Options

A. `|{:(A,B,E),(0,0,1),(0,1,0),(1,0,1),(1,1,0):}:|`
B. `|{:(A,B,E),(0,0,1),(0,1,0),(1,0,0),(1,1,0):}:|`
C. `|{:(A,B,E),(0,0,0),(0,1,1),(1,0,0),(1,1,1):}:|`
D. `|{:(A,B,E),(0,0,0),(0,1,1),(1,0,1),(1,1,0):}:|`

Answer

C

Explanation

In circuit, `C=A.B` and `D=barA.B, E=C+D=(A.B)+(barA.B)`
The truth table of this arrangement of gates will be as given below:
`|{:(A,B,bar(A),C=A.B,d=bar(A).B,E=(C+D)),(0,0,1,0,0,0),(0,1,1,0,1,1),(1,0,0,0,0,1),(1,1,0,1,0,1):}:|`