The circuit shown in figure (1) Contains two diodes each with a forward resistance of `50 ohm` and with infinite reverse resistance. If the battery voltage is `6 V`, the current through the `100 ohm` resistance is.
.

Options

A. zero
B. 0.02
C. 0.03
D. 0.36

Answer

B

Explanation

Here, `V=6V`, Resistance of `D_(1)=50Omega`
Since `D_(1)` is forward biased and `D_(2)` is reverse biased. So `D_(1)` conducts and `D_(2)` will not conduct. As all the resistors are in series, so total resistance in the circuit containing `D_(1)`
`=50Omega+150Omega+100Omega=300Omega`
Current in the circuit, `I=(6V)/(300Omega)=1/50=0.02A`