The currect voltage relation of a diode is given by `1 = (e^(van v//T) -1 )mA` where the applied volied `V` is in volts and the tempetature `T` is in degree kelvin if a student make an error meassurting `+- 01 V` while measuring the current of `5 mA at 300 K` what be the error in the value of current in `mA`

Options

A. 0.5 mA
B. 0.05 mA
C. 0.2 mA
D. 0.02 mA

Answer

C

Explanation

Given, `I=(e^(1000V//T)-1) mA`
When `I=5mA, then 5=e^(1000V//T)-1`
or `e^(1000V//T)=6mA`
Now `dI=(e^(1000V//T))xx1000/TdV`
`=(6 mA)xx1000/300xx(0.01)=0.2 mA`