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In the following common emitter configur...

In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be

A

10 mV

B

0.1 V

C

1.0 V

D

10 V

Text Solution

Verified by Experts

The correct Answer is:
C
`A_(V)=(DeltaV_(0))/(DeltaV_(i))=beta.R_(0)/R_(i) or DeltaV_(0)=DeltaV_(i)beta.R_(0)/R_(i)`
`=10^(-3)xx100xx(10/1)=1` volt
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