A CE amplifier has a voltage gain 50, an input impedance of 1000 ohm, and an output impendance of 200 ohm. The power gain of the amplifier will be

Options

A. 24 dB
B. 41 dB
C. 250 dB
D. 12500 dB

Answer

B

Explanation

Power gain in `dB =10 log.P_(0)/P_(i)=10log .(V_(0)^(2)//R_(0))/(V_(i)^(2)//R_(i))`
`=10 log.(V_(0)/V_(i))^(2)xxR_(i)/R_(0) =10 log .(50)^(2)xx1000/200`
`=10 log 12500=10xx4.0969~~41 dB`