In a common emitter configuration, a transistor has `beta=50` and input resistance `1kOmega`. If the peak value of a.c. input is 0.01 V then the peak value of collector current is

Options

A. `0.01 muA`
B. `0.25 muA`
C. `100 muA`
D. `500 muA`

Answer

D

Explanation

Here, `beta=50, R_(i)=1 kOmega=10^(3)Omega`,
`V_(i)=0.01 V =10^(-2)V`
`I_=V_(i)/R_(i)=(10^(-2)V)/(10^(3)Omega)=10^(-5)A`
`I_=betaI_=50xx10^(-5)=500xx10^(-6)A=500 muA`