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The Boolean expression P+bar(P)Q, where ...

The Boolean expression `P+bar(P)Q`, where P and Q are the inputs of the logic circuit, represents

A

AND gate

B

NAND gate

C

NOT gate

D

OR gate

Text Solution

Verified by Experts

The correct Answer is:
D

We draw a truth table for the expression `P+bar(P).Q` as given below
`|{:(P,Q,bar(P),bar(P).Q,P+bar(P.Q)),(0,0,1,0,0),(0,1,1,1,1),(1,0,0,0,1),(1,1,0,0,1):}:|`
We note that output is `1` when either of the input is `1`. Thus the logic circuit works as OR gate.
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