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A transistor is connected in common emit...

A transistor is connected in common emitter mode. The collector supply is 10 volt and the voltage drop across resistor of `1 kOmega` in the collector circuit is 0.5 volt. If the current gain beta is 49, then

A

the base current is `50 muA`

B

current gain `alpha` is `0.98`

C

the emitter current is about `510 muA`

D

the base current is `30 muA`

Text Solution

Verified by Experts

The correct Answer is:
B, C

Here, `V=0.5, R=1000Omega, V_(C)=0.5V, beta=49`
`I_(C)=V_C/R=0.5/1000=0.5 mA~~510 muA`
As, `beta=alpha/(1-alpha)`
So, `49=alpha/(1-alpha) or 49-49 alpha=alpha`
or `49=50alpha :. alpha=49/50=0.98`
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