For a transistor connected in common emitter mode, the voltage drop across the collector is 2V and beta is 50. If `R_(c)` is `2 kOmega`, the base current is `axx10^(-5) A`. What is the value of a ?

Answer

B

Explanation

Voltage drop across collector `=I_(c)R_(c)`
`:. 2=I_(c)xx(2xx10^(3)) or I_(c)=10^(-3) A`
`I_(b)=I_c/beta=10^(-3)/50=2xx10^(-5) A`