The mean free path of conduction electrons in copper is about `4.0xx10^(-8) m`. The electric field which can give on the average `2.4 eV` energy to conduction electron in copper block is `axx10^(7) V m^(-1)`. What is the integer value of a?

Explanation

To solve the problem, we need to find the integer value of \( a \) in the expression for the electric field \( E = a \times 10^7 \, \text{V/m} \) that gives an average energy of \( 2.4 \, \text{eV} \) to conduction electrons in copper, with a mean free path of \( 4.0 \times 10^{-8} \, \text{m} \).

### Step-by-Step Solution:

1. **Convert Energy from eV to Joules**:
The energy given is \( 2.4 \, \text{eV} \). We need to convert this to joules using the conversion factor \( 1 \, \text{eV} = 1.6 \times 10^{-19} \, \text{J} \).
\[
\text{Energy in Joules} = 2.4 \, \text{eV} \times 1.6 \times 10^{-19} \, \text{J/eV} = 3.84 \times 10^{-19} \, \text{J}
...