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Statement-1 : A transistor with common e...

Statement-1 : A transistor with common emitter mode has current gain `50`. When base current is `5 muA`, the emitter current is `0.255 mA`.
Statement-2 : `I_(e)=I_(b)+I_(c)`
and `beta=I_c//I_b`

A

Statement-1 is true, Statement-2 is true, Statement-2 is a correct explanation of Statement-1.

B

Statement-1 is true, Statement-2 is true, Statement-2 is not a correct explanation of Statement-1.

C

Statement-1 is true, Statement-2 is false.

D

Statement-1 is false, Statement-2 is true.

Text Solution

Verified by Experts

The correct Answer is:
A

Here, both statement-1 and statement-2 are correct and statement-2 is correct explanation of statement-1. As `I_(e)=I_(b)+I_(c)=I_(b)+betaI_(b)`
`=I_(b)(beta+1)=5mu A(50+1)`
`=255 muA=0.255 mA`
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