A specimen of silicon is to be made p-type semiconductor. For this one atom of indium, on an average is doped in `5xx10^(7)` silicon atoms. If the number density of silicon is `5xx10^(28) "atoms"//m^(3)`, then the number of acceptor atoms per `cm^(3)` is

Options

A. `10^(21)`
B. `10^(14)`
C. `10^(15)`
D. `10^(12)`

Answer

C

Explanation

No. density of silicon `=5xx10^(28) "atoms"//m^(3)`
`=5xx10^(22) "atoms"//em^(3)`
No. of acceptor `"atoms"//cm^(3)`
`=5xx10^(22)//(5xx10^(7))=10^(15)//cm^(3)`