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Calculate the values of relative permitt...

Calculate the values of relative permittivity of E and F regions of the ionosphere in the case of an electromagnetic wave of frequency 50 MHz. Given electron density for E and F regions is `10^(11)m^(-3) and 8 xx 10^(11)m^(-3)` respectively.

Text Solution

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For E-region, `N = 10^11 m^(-3)`
`v = 50MHz = 50 xx 10^6 Hz`
`varepsilon_r = 1 - (81.45N)/v^2 = 1- (81.45 xx 10^(11))/(50 xx 10^6)^2`
`= 1- 0.003258 = 0.996742 ~~ 0.997`
For F - region `N = 8 xx 10^(11) m^(-3)`
`:. varepsilon_r = 1- (81.45xx 8 xx10^(11))/(50 xx 10^6)^2 = 1-0.026 = 0.974`.
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