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What is the value of frequency at which ...

What is the value of frequency at which an e.m. wave must be propagated for the D - region to have a refractive index of 0.49 ? Electron density for D-layer is `10^(9) m^(-3)`.

Text Solution

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Here, `mu = 0.49 , N = 10^9 m^(-3), v = ?`
As `mu_r = mu/mu_0 = sqrt(1-(81.45N)/v^2)`
`:. 0.49 = sqrt(1-((81.45 xx 10^9))/v^2)`
or `0.24 = 1- (81.45 xx 10^9)/v^2`
or `v = ((81.45 xx 10^9)/(1-0.24))^(1//2) = 3.27 xx 10^5 Hz` .
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