Home
Class 12
PHYSICS
How many GPS satellites are required to ...

How many GPS satellites are required to locate the position of a person at some height above the earth's surface?

Text Solution

Verified by Experts

When a person is at some height above the
earth's surface, we need distance information
form 4 GPS satellites to determine his position
and altitude.
Promotional Banner

Topper's Solved these Questions

  • COMMUNICATION SYSTEMS

    PRADEEP|Exercise Short A/Q (3 marks)|8 Videos

  • COMMUNICATION SYSTEMS

    PRADEEP|Exercise Long answer questions|3 Videos

  • ATOMS AND NUCLEI

    PRADEEP|Exercise Assertion- Reason type question 12|1 Videos

  • CURRENT ELECTRICITY

    PRADEEP|Exercise Problems for Practice (B)|2 Videos

Similar Questions

Explore conceptually related problems

Calculate the time taken by a satellite for one revolution revolution revolving at a height of 6400 km above the earth's surface with velocity 5.6 km/s .

The ratio of binding energy of a satellite at rest on earth's surface to the binding energy of a satellite of same mass revolving around of the earth at a height h above the earth's surface is (R = radius of the earth).

Calculate the work required to raise a body of mass m to a height h just above the earth's surface. Radius of the earth is R and acceleration due to gravity at the earth's surface is g.

A remote sensing satellite of the earth revolves in a circular orbit at a height of 250 km above the earth's surface. What is the (i) orbital speed and (ii) period of revolution of the satellite ? Radius of the earth, R=6.38xx10^(6) m, and acceleration due to gravity on the surface of the earth, g=9.8 ms^(-2) .

How many natural satellites does the earth have?

Communication satellites revolve at a height of (over earth’s surface) ,

Communication satellites revolve at a height of (over earth’s surface) ,

An artificial satellite completes a circle around earth in 120 minutes. Calculate the height of the satellite above the earth's surface. Take, radius of earth = 6,400 km g = 9.8 m//s^(2)