A broadcast `AM` transmitter radiates ` 50 kW` of carrier power . What will be the radiated power at `50%` modulation ?

Answer

56.25 kW

Explanation

`P_(t) = P_( c ) ( 1 + (mu^(2))/(2)) = 50 ( 1 + (1)/(8))`
`= (450)/(8) = 56.25 kW`